A bird flies for four sec with velocity v=t-2 m/s calculte displacement and distance covered

Use graphical method.... well... this is easier than using calculus i feel...

First, take t=o as origin. plot velocity vs time graph (taking t in x axis). Corresponding to t=0, find the velocity using relation v=t-2 m/s. That will come out as -2m/s. Plot -2m/s on the negative direction of y axis. Then take v=o and find the time from the same relation which comes out to be 2s. Thus at 2 s , the particle is either at rest or in other words, comes back to it’s intial position . Draw a line joining -2m/s to the time axis at 2s. Next take t=4s which is the total time of motion in this case. You will get it’s corresponding velocity as +2m/s . Plot the same in the positive direction of y axis. Calculate the area enclosed by both the triangles formed. as the area under the v-t graph gives u the displacement. add both of them. [note: the velocity -2m/s will give negative displacement since both of them are vectors and sign has to be taken into consideration] To find distance, do not take the negative signs into consideration as distance is a scalar quantity and is always positive in magnitude.So add the areas of both triangles ignoring the signs to get the distance.