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A bead of mass m moves with constant speed v' along a thin and smooth wire bent to form a curve defined as y=(0.5 m inverse)x^2.The wire lies in horizontal plane.The impulse imparted on the bead while it moves from point A(1.73 m,1.5m) to point B(-1.73 m,1.5m) is. 
A)1.73mv' B)mv'/1.73 C)mv' D)zero
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Course Features

  • 110 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


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