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Grade 12Mechanics

A baseball with initial velocity v0= 8m/s is thrown to a wall 7m away. Determine the h where the ball hits the wall

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5 Years agoGrade 12
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ApprovedApproved Tutor Answer11 Months ago

To find out where the baseball hits the wall, we need to analyze the motion of the ball in both the horizontal and vertical directions. The ball is thrown with an initial velocity of 8 m/s towards a wall that is 7 meters away. We can break this problem down into a few logical steps.

Understanding the Motion

The baseball's motion can be described using the principles of projectile motion. In this case, we can assume that the ball is thrown at an angle, which affects its vertical position when it reaches the wall. If the ball is thrown horizontally, the height at which it hits the wall will be different than if it is thrown at an angle.

Step 1: Calculate the Time of Flight

First, we need to determine how long it takes for the baseball to reach the wall. This can be calculated using the formula:

  • Time (t) = Distance / Horizontal Velocity

Given that the distance to the wall is 7 meters and the initial horizontal velocity (v0) is 8 m/s, we can plug in the values:

  • t = 7 m / 8 m/s = 0.875 seconds

Step 2: Analyze Vertical Motion

Next, we need to consider the vertical motion of the baseball. If the ball is thrown at an angle, we need to know that angle to calculate the vertical component of the initial velocity. However, if we assume it is thrown horizontally, the initial vertical velocity is 0 m/s. The vertical motion can be described by the equation:

  • Vertical Displacement (h) = Initial Vertical Velocity × Time + 0.5 × g × t²

Here, g is the acceleration due to gravity, approximately 9.81 m/s². Since the initial vertical velocity is 0, the equation simplifies to:

  • h = 0.5 × g × t²

Now, substituting the values:

  • h = 0.5 × 9.81 m/s² × (0.875 s)²
  • h = 0.5 × 9.81 m/s² × 0.765625 s²
  • h ≈ 3.75 m

Final Result

Therefore, if the baseball is thrown horizontally, it will hit the wall at a height of approximately 3.75 meters. If it were thrown at an angle, we would need the angle of projection to determine the exact height at which it strikes the wall. This example illustrates how both horizontal and vertical motions are interrelated in projectile motion.