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A ball thrown vertically upwards with aspeed of 19.6m/s from thetop of tower returns to the earth in 6 s.Find the height of the tower
Time taken to reach highest pointt=u/gt=19.6/9.8t=2sMaximum height reached h=u²/2g=19.6Total time of flight =6sTime of ascent=2sThus Time of descent =4sHeight covered in reaching the earthH=1/2g(16)=78.4Height of tower=H-h=58.8m
I am taking downward direction as positive and upward as negative.h = – ut +½*gt2h = – 19.6*6 + ½*9.8*62h = 19.6*6(1.5 – 1) = 58.8 mHope it clears.
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