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A ball thrown down the incline strikes a point on incline 25 m below the horizontal. If ball rises to a maximum height of 20m above the point of projection find the angle of projection with the horizontal

Kumar Sambhav , 6 Years ago
Grade 12th pass
anser 1 Answers
Vikas TU
Dear student 
20=u^2sin^2x/2g⇒usinα=20
−25=20t−1/210t^2⇒t=5s
75=(ucosα)t
Solve to get tanα=4/3
good luck 
Last Activity: 5 Years ago
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