MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Grade: 11
        
a ball rolls without slipping. the radius of gyration of the ball about an axis passing through its centre of mass is k. if radius of the ball be R then fraction of total energy associated with its rotational energy in terms of k and R is what???      
i didnt understand the question so will u plzzz explain??😄
one year ago

Answers : (1)

Arun
21522 Points
							
Moment of inertia = I= MK²

1. ball is a solid sphere
I= 2/5 MR²
 rotational KE= 1/2w²= 1/2 MK²w²

total energy= 1/2 Iw² +1/2 Mv²

rolling, without slipping
v= Rw
total energy= 1/2 Iw² +1/2 MR²v²
1/2 MK²w² + 1/2 MR²w²
w²M/2= (K² + R²)

Fraction of total Energy associated with KE
1/2MK²w² divided by w²M/2 (K²+R²) = 
K²/ (K²+ R²)
one year ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies


Course Features

  • 101 Video Lectures
  • Revision Notes
  • Previous Year Papers
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Test paper with Video Solution


Course Features

  • 110 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details