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Grade: 11
`        a ball rolls without slipping. the radius of gyration of the ball about an axis passing through its centre of mass is k. if radius of the ball be R then fraction of total energy associated with its rotational energy in terms of k and R is what???Â  Â  Â Â i didnt understand the question so will u plzzz explain??ðŸ˜„`
2 years ago

Answers : (1)

Arun
24483 Points
```							Moment of inertia = I= MKÂ²1. ball is a solid sphereI= 2/5 MRÂ²Â rotational KE= 1/2wÂ²= 1/2 MKÂ²wÂ²total energy= 1/2 IwÂ² +1/2 MvÂ²rolling, without slippingv= Rwtotal energy= 1/2 IwÂ² +1/2 MRÂ²vÂ²1/2 MKÂ²wÂ² + 1/2 MRÂ²wÂ²wÂ²M/2= (KÂ² + RÂ²)Fraction of total Energy associated with KE1/2MKÂ²wÂ² divided by wÂ²M/2 (KÂ²+RÂ²) =Â KÂ²/ (KÂ²+ RÂ²)
```
2 years ago
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