a ball rolls without slipping. the radius of gyration of the ball about an axis passing through its centre of mass is k. if radius of the ball be R then fraction of total energy associated with its rotational energy in terms of k and R is what???i didnt understand the question so will u plzzz explain??😄
Sayani , 6 Years ago
Grade 11
1 Answers
Arun
Last Activity: 6 Years ago
Moment of inertia = I= MK²
1. ball is a solid sphere I= 2/5 MR² rotational KE= 1/2w²= 1/2 MK²w²
total energy= 1/2 Iw² +1/2 Mv²
rolling, without slipping v= Rw total energy= 1/2 Iw² +1/2 MR²v² 1/2 MK²w² + 1/2 MR²w² w²M/2= (K² + R²)
Fraction of total Energy associated with KE 1/2MK²w² divided by w²M/2 (K²+R²) =