A ball of mass 0.3 kg is released from a tower of height 100 m, simultaneously a bullet of mass 0.2 kg fired vertically upward from point just below it with speed 100 m/s find height attained above the tower by combined mass system after collision

Question

Arun · Answer

Dear Sumit velocity of combined mass = 0.5*v = 0.3*0 + 0.2*100 = 40 m/s height attained above the tower = u 2 /2g = 1600/20 = 80m Hope it helps Regards Arun

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A ball of mass 0.3 kg is released from a tower of height 100 m, simultaneously a bullet of mass 0.2 kg fired vertically upward from point just below it with speed 100 m/s find height attained above the tower by combined mass system after collision

A ball of mass 0.3 kg is released from a tower of height 100 m, simultaneously a bullet of mass 0.2 kg fired vertically upward from point just below it with speed 100 m/s find height attained above the tower by combined mass system after collision

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A ball of mass 0.3 kg is released from a tower of height 100 m, simultaneously a bullet of mass 0.2 kg fired vertically upward from point just below it with speed 100 m/s find height attained above the tower by combined mass system after collision

A ball of mass 0.3 kg is released from a tower of height 100 m, simultaneously a bullet of mass 0.2 kg fired vertically upward from point just below it with speed 100 m/s find height attained above the tower by combined mass system after collision

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