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Grade 11Mechanics

A ball is thrown vertically upwards with speed 40m/s , the distance covered by the ball during the last 3 second of its ascending motion is

Profile image of Ritika
8 Years agoGrade 11
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1 Answer

Profile image of Khimraj
8 Years ago
let time taken to reach maximum height is t
then
0 = 40 – gt
t = 4sec
distance covered in last 3 sec = distance coveres in 4 sec – distance covered in first second
= (40*4 – ½*10*42) – (40*1 – ½*10*12
= (160 – 80) – (40 – 5)
= 80 – 35 = 55m.
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