Click to Chat

1800-1023-196

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
`        A ball is thrown vertically upwards with a velocity of 10m/s . It returns to the ground with the velocity of 9m/s . If g=9.8m/s^2 ,then the max height attained by the ball is nearly?`
one year ago

Ram Prakash
29 Points
```							u=10 m/sa =-9.8 m/s^2( since g acts downwards)v= 0 since v^2 = u^2 +2astherefores= v^2 -u^2 / 2 a  = 0- 100 /2×-9.8  = -100 / -19.6  = 5.1020 m   = -100 /
```
one year ago
Khimraj
3008 Points
```							Let the mass of the body be M. It is thrown up with a velocity of 10 m/s, but returns to the ground with a velocity of 9 m/s.It means that in upward and downward journey it lost energy due to dissipative forces equal to kinetic energy of 1m/s, i.e. it lost energy equivalent to kinetic energy of ½ m/s either way.So it is equivalent to saying that it was thrown up with an initial velocity of 9.5 m/s, rather than 10m/s, and forget about dissipative forces.At the highest point the entire kinetic energy is converted into potential energy. Let the height achieved be h. Then½ m v² = m g h,==> h = v²/2g = 9.5²/2×9.8= 4.61 m.The body shall achieve a height of 4.61 m.
```
one year ago
Think You Can Provide A Better Answer ?

## Other Related Questions on Mechanics

View all Questions »

### Course Features

• 101 Video Lectures
• Revision Notes
• Previous Year Papers
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Test paper with Video Solution

### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions