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a ball is thrown vertically upwards with a certain velocity. while moving upwards it passes a certain pointA after time t1, and takes furthur time t2 to reach the point of projection. then height of A

Ekta Singh , 7 Years ago
Grade 11
anser 1 Answers
Vikas TU

Last Activity: 7 Years ago

Dear Student,
From Netwon’s second law of equation we get,
H= ut1-gt1^2/2
t1+t2=2u/g
=>u=g(t1+t2)/2

h=g(t1+t2)t1/2 – gt1^2/2
=gt1(t1+t2-t2)/2
=gt1t2/2.
Cheers!!
Regards,
Vikas (B. Tech. 4th year
Thapar University)

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