Mechanics> A ball is thrown vertically upwards.When ...

A ball is thrown vertically upwards.When it is half of its maximum height its velocity is 10 metre per second ,find the maximum height reached by ball.

anuj , 6 Years ago

Grade 9

2 Answers

Vikas TU

Hiii

V^2 = u ^2 + 2as

v = 0

so , u^2 = 20H

Now, apply this in middle , V = 10m/s

and s = H/2

so height comes out to be 10m

Last Activity: 6 Years ago

sree lakshmi

Let us suppose that the ball was thrown with an initial speed u
Now, let us assume the Maximum Height reached is H

A constant acceleration g=10m/s² is acting in downward direction.

Let us consider the motion from start to Max Height.

In this time interval, final velocity is zero, and distance travelled is H. We have:

$v^{2} = u^{2}+2as$

$\rightarrow 0^{2}=u^{2}+2\times (-10)H$

$u^{2}=20H$

Now, let us consider the time from start to when the ball reaches half the maximum height. Now, in this time interval, final velocity is 10 m/s, and Distance Travelled is H/2

$v^{2} = u^{2}+2as$

$10^{2}=20H +2(-10)H/2$

$100=20H-10H$

$10H=100$

H= 10m

Thus, maximum height reached is 10 metres.

Last Activity: 6 Years ago

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Mechanics> A ball is thrown vertically upwards.When ...

A ball is thrown vertically upwards.When it is half of its maximum height its velocity is 10 metre per second ,find the maximum height reached by ball.

anuj , 6 Years ago

Vikas TU

sree lakshmi

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