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a ball is thrown vertically upwards from the groung it crosses a point at a height of 25 m twice at an interval of 4 second. find the velocity with which the ball was thrown

Sådhnâ Sharma , 9 Years ago

Grade 11

1 Answers

Vikas TU

Time of flight is actually given for crossing the point actually two times.

with projection at hetha = 90 degree

4 = 2v/g

v = 2g m/s

This is the velocity at 25 meter initially (crossing first time).

Now calculating velocity (initaial)

at height of 25 m.

Sign convention taking upwards positive and downwards negative.

From 3rd law of eqn.

v^2 = u^2 – 2gs

(2g)^2 = u^2 – 2g*25

u^2 = 4g^2 +50g

u^2 = 400 + 500

u^2 = 900

u = 30 m/s

Hence the velocity with the ball was thrown was 30 m/s.

Plz Approve!

Last Activity: 9 Years ago

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Mechanics> a ball is thrown vertically upwards from ...

a ball is thrown vertically upwards from the groung it crosses a point at a height of 25 m twice at an interval of 4 second. find the velocity with which the ball was thrown

Sådhnâ Sharma , 9 Years ago

Vikas TU

LIVE ONLINE CLASSES

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