MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Grade: 12
        
a ball is thrown vertically upwards from the foot of a tower.it crosses the top of the tower twice after an interval of 4s and reaches the foot of the tower 8s after it was thrown.what is the height of the tower??
3 months ago

Answers : (2)

Arun
24726 Points
							
Dear Student
 
time taken to go upto U and then come back to the ground required 8 sec.
So 4 s up then 4 s in coming down.
the time taken between climbing from T to U and then coming to T again(crossing T twice) =4 s
so time taken to go upto T from the ground=(8 - 4)/2=2s
now if we consider the journey from ground to U:
0=u-4x10 ....... putting in 1st eq.
u=40 m/s
now tower height:H=
H=40x2-1/2 x10x2x2.....putting in second eq
H=60 m
 
3 months ago
Vikas TU
11680 Points
3 months ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies


Course Features

  • 101 Video Lectures
  • Revision Notes
  • Previous Year Papers
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Test paper with Video Solution


Course Features

  • 110 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details