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A ball is thrown vertically upward with a velocity 10m/s and it returns the ground with speed 8m/s . There exist a constant air resistance . The maximum height attained by ball is

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3 years ago

```							Initial speed of ball = U0 = 10m/s.Final speed of ball = Uf = 0m/s (at maximum height).Gravitational acceleration = g = 9.8m/s (In downward direction).Let maximumum Height cover by ball = H.Let accileration due to Air resistance working on it = R.So apply kinematics 3rd equation from ground to maximum height.    V2 = U2 + 2*a*H     02 = (10)2 +2*(-g-R)*H.  so, g+R = 50/H  ------------------(1) Now apply kinematics 3rd equation from maximum height to ground.      82= 02 + 2*(g-R)*H.   So, g-R = 32/H ------------------(2)Adding equation 1st and 2nd , we get      H = 82/(2*g) = 82/(2*9.8) = 4.18367m.
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3 years ago
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