Grade 11Mechanics

A ball is thrown vertically upward with a velocity of 22m/s from a point 4.6m above the ground.
Find the velocity with which it hits the ground?
If it rebounds with a velocity which is half the velocity it hits the ground,
Find the greatest height after the bounce?

Vidura

10 Years agoGrade 11

1 Answer

Vikas TU

Approved Tutor Answer10 Years ago

From point 4.6 m, with velocity 22 m/s,

maximum height it travels = u^2/2g = 22*22/20 = 24.2 m

that means

at total height if we includes height of building too,

from 4.6m + 24.2 m = 28.8m we will apply 2^nd law of eqn.

therfore,

from 28.8 m velocity of ball =0

hence final velocity at ground,

v^2 = 0^2 + 2*g*28.8

v^2 = 576

v = 24 m/s

If it rebounds with a velocity which is half the velocity it hits the ground,

.i.e Greatest height, H = (v/2)^2/2g = 144/20 = 7.2 m

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A ball is thrown vertically upward with a velocity of 22m/s from a point 4.6m above the ground.Find the velocity with which it hits the ground?If it rebounds with a velocity which is half the velocity it hits the ground,Find the greatest height after the bounce?

Vidura

1 Answer

Vikas TU

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A ball is thrown vertically upward with a velocity of 22m/s from a point 4.6m above the ground.
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