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A ball is thrown vertically upward with a velocity u from the top of a tower.if it strikes the ground with velocity 3u, the time taken by the ball to reach the ground is
4u/g is the ans correct
well it is so simple a=(V-U)/there a=-g v=-3u u=u find t
initial velocity = u =-ufinal velocity = v = 3uacceleration due to gravity = g v = u + gt 3u = -u + gt3u+u/g = t4u/g = t
WellSince u is going against gravity, u = -uAnd final velocity is 3u so, v = 3u Time can be calculated V = u + gt 3u = -u + gtSo, 4u/g = tHope this will help. 4u = gtSo, t = 4u
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