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A ball is thrown vertically upward. It was observed at a height h twice with a time interval delta t. The initial velocity of the ball is ..........
write the eqn. for the ball.h = ut – 0.5gt^2............................(1)solve the quadratic eqn. (1)and u would get the two values of t in terms of u and h.here both the time would be acceptable as It was observed at a height h twice with a time interval delta t.thus,one root suppose let t1 and the other say t2.both has differene of t or for samll t that is dt.Therefore,t1 - t2 = dtThus solving the all eqns.u would get (dt)^2 make that zero as it is ver small.u would get finally,u = root(2gh).
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