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`        A ball is thrown horizontally with a velocity of 9.8m/s from a tower 49m high.its velocity after one sec is a)9.8 b)9.8√2 c)19.6 d)28.4`
one year ago

763 Points
```							We can calculate it by finding horizontal and vertical component of velocity after 1 second.Both horizontal and vertical component of velocity after 1 second is 9.8 Therefore resultant velocity is equal to 9.8√2.Hence (b) is the correct option.
```
one year ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions