A ball is thrown from the ground into the air. At a height of 9.1 m, the velocity is observed to be (x axis horizontal, y axis vertical and up). (a) To what maximum height will the ball rise? (b) What will be the total horizontal distance traveled by the ball? (c) What is the velocity of the ball (magnitude and direction) the instant before it hits the ground?

Question

Jitender Pal · Answer

Therefore, the maximum height to which the ball rises is 11 m. .

Round off to two significant figures,
x = 23 m
Therefore, the horizontal distance travelled by the ball is 23 m.

Round of to two significant figures,

The magnitude of vector $\overrightarrow{v}_{f}$ is:

The angle subtended by the vector $\overrightarrow{v}_{f}$ relative to horizontal is:

The negative sign indicates the fact that the angle is measured in clockwise direction.
Therefore, the vector $\overrightarrow{v}_{f}$ is directed at 63° measured in clockwise direction with respect to horizontal.

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