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`        A ball is thrown forward from the top of a cliff with a velocity of 10ms. The height of the cliff above the ground is 45m. Calculate the distance of the ball to the hirizontal just before hitting the ground Please answer`
one month ago

Saurabh Koranglekar
8380 Points
```							Dear studentSince the velocity is horizontalVertical velocity can be assumed to be 0Time required to reach ground is (2*45/g)^0.5 = 3 secNow horizontal dist = 10*3 = 30 metersRegards
```
one month ago
Sandeep
103 Points
```							The answer would be 30 m as ....the time taken by the ball toreach the drowns is 3 second by half at square =45so 3*10= 30............................ Answer
```
one month ago
Vikas TU
11761 Points
```							Please refer https://www.askiitians.com/forums/Mechanics/a-ball-is-thrown-forward-from-the-top-of-a-cliff-w_258878.htm
```
one month ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions