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A ball is thrown forward from the top of a cliff with a velocity of 10ms. The height of the cliff above the ground is 45m. Calculate the distance of the ball to the hirizontal just before hitting the ground

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10 months ago Saurabh Koranglekar
10233 Points
```							Dear studentTime for fall = sqrt( 2*h/g) = sqrt ( 2*45/10)= 3 secHorizontal distance travelled by the ball= 3 * speed horizontal= 3* 10 = 30 mRegards
```
10 months ago
```							Dear student Horizontal velocity is irrelevant. Horizontal and vertical motion are independent of each other.h = Vin*t + 1/2 gt^2 h = 1/2 gt^2 From heret = sqrt(2h/g)t = 3sec Horizontal distance travelled by the ball= 3 * speed horizontal= 3* 10 = 30 m
```
10 months ago
```							Dear Student, Horizontal and vertical motion are independent of each other.h = Vin*t + 1/2 gt^2 h = 1/2 gt^2 From heret = sqrt(2h/g)t = 3sec Horizontal distance travelled by the ball= 3 * speed horizontal= 3* 10 = 30 mHorizontal velocity is irrelevant. Regards
```
8 months ago
```							Time for fall = sqrt( 2*h/g) = sqrt ( 2*45/10)= 3 secHorizontal distance travelled by the ball= 3 * speed horizontal= 3* 10 = 30 m
```
5 months ago
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