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Grade: 9
        
A ball is thrown forward from the top of a cliff with a velocity of 10ms. The height of the cliff above the ground is 45m. Calculate the distance of the ball to the hirizontal just before hitting the ground
2 months ago

Answers : (3)

Saurabh Koranglekar
askIITians Faculty
4093 Points
							Dear student

Time for fall = sqrt( 2*h/g) = sqrt ( 2*45/10)= 3 sec

Horizontal distance travelled by the ball= 3 * speed horizontal
= 3* 10 = 30 m

Regards
2 months ago
Vikas TU
10603 Points
							
Dear student 
Horizontal velocity is irrelevant. Horizontal and vertical motion are independent of each other.
h = Vin*t + 1/2 gt^2 
h = 1/2 gt^2 
From here
t = sqrt(2h/g)
t = 3sec 
Horizontal distance travelled by the ball= 3 * speed horizontal= 3* 10 = 30 m
2 months ago
aswanth nayak
100 Points
							
Dear Student,
 
Horizontal and vertical motion are independent of each other.
h = Vin*t + 1/2 gt^2 
h = 1/2 gt^2 
From here
t = sqrt(2h/g)
t = 3sec 
Horizontal distance travelled by the ball= 3 * speed horizontal= 3* 10 = 30 m
Horizontal velocity is irrelevant.
 
Regards
one month ago
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