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A ball is projected from top of a tower with a velocity of 5m/s at an angle of 53 degree to horizontal.Its speed when it is at a height of 0.45m from the point of projection is:

A ball is projected from top of a tower with a velocity of 5m/s at an angle of 53 degree to horizontal.Its speed when it is at a height of 0.45m from the point of projection is:

Grade:11

1 Answers

Arun
25750 Points
5 years ago
 

The vertical component of the velocity= 4 m/s

         The horizental component is=3m/s

The final vertical velocity is=√(4² - 2*g*0.45) m/s

                                    =√(16-9)

                                     =√7 m/s

The horizental component is is same = 3m/s

Hence the total speed is=√(9+7)=4m/s(ans)

 

Regards

Arun

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