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A ball is projected from top of a tower with a velocity of 5m/s at an angle of 53 degree to horizontal.Its speed when it is at a height of 0.45m from the point of projection is: A ball is projected from top of a tower with a velocity of 5m/s at an angle of 53 degree to horizontal.Its speed when it is at a height of 0.45m from the point of projection is:
The vertical component of the velocity= 4 m/s The horizental component is=3m/sThe final vertical velocity is=√(4² - 2*g*0.45) m/s =√(16-9) =√7 m/sThe horizental component is is same = 3m/sHence the total speed is=√(9+7)=4m/s(ans) RegardsArun
The vertical component of the velocity= 4 m/s
The horizental component is=3m/s
The final vertical velocity is=√(4² - 2*g*0.45) m/s
=√(16-9)
=√7 m/s
The horizental component is is same = 3m/s
Hence the total speed is=√(9+7)=4m/s(ans)
Regards
Arun
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