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A ball is projected from ground with velocity 40m/s . After two seconds, the velocuveof ball becomes horizontal. The angle of projection of ball with horizontal is A ball is projected from ground with velocity 40m/s . After two seconds, the velocuveof ball becomes horizontal. The angle of projection of ball with horizontal is
30° The velocity of particle is horizontal at highest point of motion therefore time taken to reach at highest point is 2sTherefore time of flight will be two times 2s that is 4s Now apllat=(2usintheta )/gU get sintheta =halfTheta is 30°Don't forget to approve and have a visit on my profileHope this helps u :)😁
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