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Grade 11Mechanics

A ball is dropped from the top of the tower Of height h. It covers a distance of h/2 in the lasy second of its motion. How long does the ball remains in the air?

Profile image of Aseda Baamah
7 Years agoGrade 11
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1 Answer

Profile image of Arun
7 Years ago

Let the time during which the ball remains in air be T seconds

Then we have h=1/2 gT^2 …(1)

Now distance travelled by ball in nth second is given by Sn=g/2(2n-1)

h/2=g/2(2T-1)…(2)

Substituting h from (1) in (2) we get

T^2=4T-2

T^2–4T+2=0

Which gives T=3.41 seconds