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Grade: 9

                        

a ball is dropped from a height of 15 m and bounces back with same speed. it was in contact with ground for 10 millisecond and change in momentum is -7.5m/s. find the mass

4 years ago

Answers : (1)

Vikas TU
12276 Points
							
Since u have asked twice i writing here again,
 
change in momentum is -7.5m/s.
Therfore the impulse that is J = -7.5
J = -Fdt
7.5 = F * 10 * 10^-3
F = 750 N.
that is Normal force actually exerted at the timme of contact.
Gence at that time,
N = mg (as simple)
10m = 750 
m = 75 kg.
4 years ago
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