×

#### Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Click to Chat

1800-1023-196

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
```
a ball is dropped from a height of 15 m and bounces back with same speed. it was in contact with ground for 10 millisecond and change in momentum is -7.5m/s. find the mass

```
4 years ago

## Answers : (1)

Vikas TU
14146 Points
```							Since u have asked twice i writing here again, change in momentum is -7.5m/s.Therfore the impulse that is J = -7.5J = -Fdt7.5 = F * 10 * 10^-3F = 750 N.that is Normal force actually exerted at the timme of contact.Gence at that time,N = mg (as simple)10m = 750 m = 75 kg.
```
4 years ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies

## Other Related Questions on Mechanics

View all Questions »

### Course Features

• 101 Video Lectures
• Revision Notes
• Previous Year Papers
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Test paper with Video Solution

### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions