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a ball is dropped from a height.if it takes 2 seconds to cross last 6 metres.find the height from which ball is dropped.
For last 6m distance travelled , s=6mtime=0.2sinitial velocity=?a=g=9.8m/s2s=ut+1/2at²=6=u(0.2)+1/2 x 9.8 x0.2x0.26=0.2 u + 4.9 x 0.04u=5.8/0.2u=29m/sFor distance x, u=0m/sv=29m/s [ because initial velocity will be final]a=g=9.8m/s2s= v²-u²/2a=29²-0²/2x9.8=29x29/19.6s=42.05mTotal distance=42.05 +6=48.05 m RegardsArun
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