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```
A ball is dropped from a bridge of 122.5 metres above a river . After the ball has been falling for two seconds, a second ball is thrown straight down after it. Initial velocity of second ball so that both hit the water at the same time is

```
5 years ago

Hasan Naqvi
97 Points
```							time taken by first ball to hit water can be found as s= ut + ½ gt2122.5 = ½ * 9.8 * t2t2=  25t =5  Now the next ball must cover this distance in 3 s to hit water at same time.122.5 = 3 u + ½ * 9.8 * 32122.5 = 3u + 44.13u = 78.4u= 26.133 m/s
```
5 years ago
36 Points
```							 time taken by first ball to hit water can be found as s= ut + ½ gt2122.5 = ½ * 9.8 * t2t2=  25t =5  Now the next ball must cover this distance in 3 s to hit water at same time.122.5 = 3 u + ½ * 9.8 * 32122.5 = 3u + 44.13u = 78.4u= 26.133 m/s
```
4 years ago
610 Points
```							Dear student,Please find the solution to your problem. Time taken by first ball to hit water can be found ass= ut + ½ gt2122.5 = ½ * 9.8 * t2t2=  25t =5 Now the next ball must cover this distance in 3 s to hit water at same time.122.5 = 3 u + ½ * 9.8 * 32122.5 = 3u + 44.13u = 78.4u= 26.133 m/s Thanks and regards,Kushagra
```
5 months ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions