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`        A ball is dropped from a balloon going up at a speed of 10m/s .If the balloon was at a height 75m at the time of dropping the ball ,how much time will the ball take in reaching the ground ?`
2 months ago

Arun
22539 Points
```							Initially ball is going upwards Initial velocity=u= -10m/sS=75ma=g=10m/s2From Second equation of motion s=ut+1/2at²75= - 10t +(1/2 )10 t²75=-10t +5t²5t² -10t -75=0t= 5 seconds∴ The ball will take 5 sec to reach the ground.
```
2 months ago
Khimraj
3008 Points
```							Solution :Initially ball is going upwards Initial velocity=u= -7m/sS=75ma=g=10m/s2From Second equation of motion s=ut+1/2at²70= - 7t +(1/2 )10 t²70=-7t +5t²5t² -7t -70=0t=-7±√49-4x5(-70)/2x5t=-7±√49+1400/10t =5 sec [ as t cannot be negative]∴ The ball will take 5 sec to reach the ground.
```
2 months ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions