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Grade: 11
        
A ball is at same height after time t1 and t2 from point of projection in ground to ground projectile motion then the height of the point from ground is?
6 days ago

Answers : (1)

Sushant Kumar
45 Points
							
 \frac{1}{2}gt_{1}t_{t2}
 
y=usin\Theta t -1/2gt^{2}          ---------(1)
at t1 and t2 y is same hence
usin\Theta t_{1} -1/2gt_{1}^{2}=usin\Theta t_{2} -1/2gt_{2}^{2}  --------------------(2)
from here we find value of usin thetha and put it in eq 1 where we can put t=either tor t2 both give same answer
 
hope this help
 
 
5 days ago
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