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        A ball is at same height after time t1 and t2 from point of projection in ground to ground projectile motion then the height of the point from ground is?
one year ago

Sushant Kumar
42 Points
							 $\frac{1}{2}gt_{1}t_{t2}$ $y=usin\Theta t -1/2gt^{2}$          ---------(1)at t1 and t2 y is same hence$usin\Theta t_{1} -1/2gt_{1}^{2}=usin\Theta t_{2} -1/2gt_{2}^{2}$  --------------------(2)from here we find value of usin thetha and put it in eq 1 where we can put t=either t1 or t2 both give same answer hope this help

one year ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions