A ball falls from rest under gravity on the moon such that 1st 1/2 of distance is vovered in 10seconds toatl time of the fallof ball is

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Saurabh Koranglekar · Answer

Dear student S= 0.5 (a t*t) H/2 = 0.5 ( a*100) Using H = 100a Total time for 100a from start extra time required = 10((sqrt2)-1) Regards 100a = 0.5a T *T T = 10(sqrt(2))

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A ball falls from rest under gravity on the moon such that 1st 1/2 of distance is vovered in 10seconds toatl time of the fallof ball is

_{A ball falls from rest under gravity on the moon such that 1st 1/2 of distance is vovered in 10seconds toatl time of the fallof ball is}

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A ball falls from rest under gravity on the moon such that 1st 1/2 of distance is vovered in 10seconds toatl time of the fallof ball is

A ball falls from rest under gravity on the moon such that 1st 1/2 of distance is vovered in 10seconds toatl time of the fallof ball is

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_{A ball falls from rest under gravity on the moon such that 1st 1/2 of distance is vovered in 10seconds toatl time of the fallof ball is}