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Grade 11Mechanics

A ball falls freely from a height of 1m on ground and rebounds to a height of 0.8m. Find coefficient of restitution.

Simran

10 Years agoGrade 11

2 Answers

arun

10 Years ago

let velocity of approach be $\vartheta$

then from third equation of motion

$\vartheta^2 = u^2 +2as$

and in his case $u=0$ m/s

$a=g$

$s= 1$ metres

$\Rightarrow \vartheta =\sqrt{2g}$

now let velocity of seperation is $v$

again using third equation of motion

$v^2 = u^2 +2as$

and in this case

$u=0$ m/s

$a=g$

$s = 0.8$ metres

$v=\sqrt{1.6g}$

now $e =v\div \vartheta$

$e= \sqrt{1.6\div 2}$

$e= \sqrt{0.8}$

J bat

8 Years ago

The coefficient of restitution is given bye^n = ( hn/h)^1/2 .: for 1 collision n=1 ,hn = 0.8, h=1e=(0.8)^1/2

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