#### Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Click to Chat

1800-5470-145

+91 7353221155

CART 0

• 0
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

# (a) Assuming that the drag force D is given by D = bv, show that the distance Y95 through which an object must fall from rest to reach 95% of its terminal speed is given bywhere VT is the terminal speed. (Hint: Use the result for yet) obtained in Problem 17.) (b) Using the terminal speed of 42 m/s for the baseball given in Table 4-1, calculate the 95% distance. Why does the result not agree with the value listed in Table 4-1 ?

Kevin Nash
6 years ago

Round off to three significant figures,
y95 = 368 m
Therefore, the baseball falls a distance of 368 m before attaining 95% of its terminal speed.
It is important to note that the value obtained above does not agree with the value given in table 4-1 ( 120 m). This is because when the baseball falls down both drag force and buoyant force acts on it. In the calculations the effect of buoyancy is neglected and eventually one ends up getting higher value than it should be.