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A acr is moving with a speed v along a straight horigontal road and coefficient of friction b/w road and tyre is u,then what will be the shortest disctance in which car stopped

A acr is moving with a speed v along a straight horigontal road and coefficient of friction b/w road and tyre is u,then what will be the shortest disctance in which car stopped

Grade:12th pass

1 Answers

Vikas TU
14149 Points
4 years ago
at the bottom of the tyre we apply kineteic energy theorem.
Hence,
f x y = 0.5mv^2
umgy = 0.5mv^2
y = v^2/2ug meter.
Note:\
speed at bottom of the wheel is v.

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