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A 918 kg car has four 12.7 kg wheels. When the car is moving, what fraction of the total kinetic energy of the car is due to rotation of the wheels about their axles? Assume that the wheels have the same rotational inertia as uniform disks of the same mass and size.
one year ago

Arun
23547 Points

in case the weight of wheels is included in the lump sum of 918 kg
Ek of wheels = Ekt (translational)+Ekr (rotational) :
Ek 4(1/2*m*V^2+1/2*J*ω^2) = 4(1/2m*V^2+1/2(1/2*m*r^2*V^2/r^2)) = 4*m*V^2(1/2+1/4) = 3*mV^2 = 38.1V^2 of which :
# 38.1V^2/3 is rotational
# 2*38.1V^2/3 is translational

and finally :
k1 = 100(38.1/(918/2+38.1/3)) =

nownyou cqn calculate
one year ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions