A 6 m stick of mass 60 kg is rested upon a wall. At what distance should the bottom of the stick be so that it tends to slip? Coeff of friction between stick and floor is 0.3

Question

Vikas TU · Answer

Let at x distance fro the bottom it would teds to slip. Hence the torque to its cetre of mass = 0. Therfore, (60x/l)g x (x/2) = 60(l-x)^2/2l on solving we get, x = 6/(1+ root(g)) = > 1.452 meter approx.

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A 6 m stick of mass 60 kg is rested upon a wall. At what distance should the bottom of the stick be so that it tends to slip? Coeff of friction between stick and floor is 0.3

A 6 m stick of mass 60 kg is rested upon a wall. At what distance should the bottom of the stick be so that it tends to slip? Coeff of friction between stick and floor is 0.3

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A 6 m stick of mass 60 kg is rested upon a wall. At what distance should the bottom of the stick be so that it tends to slip? Coeff of friction between stick and floor is 0.3

A 6 m stick of mass 60 kg is rested upon a wall. At what distance should the bottom of the stick be so that it tends to slip? Coeff of friction between stick and floor is 0.3

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