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`        A 6 m stick of mass 60 kg is rested upon a wall. At what distance should the bottom of the stick be so that it tends to slip? Coeff of friction between stick and floor is 0.3`
2 years ago

Vikas TU
9794 Points
```							Let at x distance fro the bottom it would teds to slip.Hence the torque to its cetre of mass = 0.Therfore,(60x/l)g x (x/2) = 60(l-x)^2/2lon solving we get,x = 6/(1+ root(g)) = > 1.452 meter approx.
```
2 years ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions