Grade 12th passMechanics

a 5kg brick of 20cm10cm8cm dimension lying on the largest basebase. It is now made to stand with lenth verticle.then amount of work done

Nitin Chaudhary

7 Years agoGrade 12th pass

2 Answers

Saurav

7 Years ago

The guy above did it wrong 😂

When it is lying on largest base height is 8cm

Therefore centre of mass will be at height 4cm

Now when length is vertical centre of mass will be at height 10 cm

Therefore change in height will be 6 cm

Change in PE =5 g 0.06J

That is 3J

Hope this helps u 😁

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Dharun J

7 Years ago

Thanks for correction saurav i didnt see this thing i forgot it while doing it thanks for remembering this to me.

First ht is 8 so pe =5g8=400j final pe =5g20 =1000 joules so w.d equal to ?pe =600j or if l is 10 then pe new=5g10=500j so ?pe =100j.

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a 5kg brick of 20cm*10cm*8cm dimension lying on the largest basebase. It is now made to stand with lenth verticle.then amount of work done

Nitin Chaudhary

2 Answers

Saurav

Dharun J

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a 5kg brick of 20cm10cm8cm dimension lying on the largest basebase. It is now made to stand with lenth verticle.then amount of work done

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