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a 5kg brick of 20cm*10cm*8cm dimension lying on the largest basebase. It is now made to stand with lenth verticle.then amount of work done

a 5kg brick of 20cm*10cm*8cm dimension lying on the largest basebase. It is now made to stand with lenth verticle.then amount of work done
 

Grade:12th pass

2 Answers

Saurav
224 Points
5 years ago
The guy above did it wrong 😂
When it is lying on largest base height is 8cm
Therefore centre of mass will be at height 4cm
 
Now when length is vertical centre of mass will be at height 10 cm 
Therefore change in height will be 6 cm 
Change in PE =5 g 0.06J
That is 3J
Hope this helps u 😁
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Dharun J
35 Points
5 years ago
Thanks for correction saurav i didnt see this thing i forgot it while doing it thanks for remembering this to me.
First ht is 8 so pe =5g8=400j final pe =5g20 =1000 joules so w.d equal to ?pe =600j or if l is 10 then pe new=5g10=500j so ?pe =100j.

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