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A 50-N force acts on a 2-kg crate that starts from rest. There is no friction. At time equals 2.0 seconds, the instantaneous rate at which the force is doing work is:
Dear student Thereis no image attached. Please repost the question with an attachment. I will be happy to help you.
I am sorry sir I do not have image for this question and if u can manage without image would be greately appreciated
Dear student instantaneous Power delivered by a moving force equals:P = force x velocityThe final velocity in this case isVf = (1/m)*(final momentum) = F*t/m= 50*2/2 = 50 m/sPower at end of interval = F*Vf = 50*50 = 2500 W
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