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Grade: 12th pass

                        

A 50-N force acts on a 2-kg crate that starts from rest. There is no friction. At time equals 2.0 seconds, the instantaneous rate at which the force is doing work is:

4 months ago

Answers : (3)

Arun
24738 Points
							
Dear student
 
Thereis no image attached. Please repost the question with an attachment. I will be happy to help you.
4 months ago
Mayank
12 Points
							
I am sorry sir I do not have image for this question and if u can manage without image would be greately appreciated
 
4 months ago
Vikas TU
12133 Points
							
Dear student 
instantaneous Power delivered by a moving force equals:
P = force x velocity
The final velocity in this case is
Vf = (1/m)*(final momentum) = F*t/m
= 50*2/2 = 50 m/s
Power at end of interval = F*Vf = 50*50 = 2500 W
 
4 months ago
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