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A 4.40-kg block is put on top of a 5.50-kg block. In order to cause the top block to slip on the bottom one, held fixed, a horizontal force of 12.0 N must be applied to the top block. The assembly of blocks is now placed on a horizontal, frictionless table; see Fig. Find (a) the maximum horizontal force F that can be applied to the lower block so that the blocks will move together, (b) the resulting acceleration of the blocks, and (c) the coefficient of static friction between the blocks.

A 4.40-kg block is put on top of a 5.50-kg block. In order to cause the top block to slip on the bottom one, held fixed, a horizontal force of 12.0 N must be applied to the top block. The assembly of blocks is now placed on a horizontal, frictionless table; see Fig. Find (a) the maximum horizontal force F that can be applied to the lower block so that the blocks will move together, (b) the resulting acceleration of the blocks, and (c) the coefficient of static friction between the blocks.

Grade:10

1 Answers

Jitender Pal
askIITians Faculty 365 Points
8 years ago
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Therefore, the maximum horizontal force F that can be applied to lower block so that the blocks move together is 27.0 N .
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Therefore, the coefficient of static friction between the blocks is 0.27 .

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