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Grade: 10

                        

A 4.40-kg block is put on top of a 5.50-kg block. In order to cause the top block to slip on the bottom one, held fixed, a horizontal force of 12.0 N must be applied to the top block. The assembly of blocks is now placed on a horizontal, frictionless table; see Fig. Find (a) the maximum horizontal force F that can be applied to the lower block so that the blocks will move together, (b) the resulting acceleration of the blocks, and (c) the coefficient of static friction between the blocks.

5 years ago

Answers : (1)

Jitender Pal
askIITians Faculty
365 Points
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Therefore, the maximum horizontal force F that can be applied to lower block so that the blocks move together is 27.0 N .
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Therefore, the coefficient of static friction between the blocks is 0.27 .
5 years ago
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Course Features

  • 110 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


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