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`         A 35 kg crate is at rest on the floor. A man attempts to push it across the floor by applying a 100 N force horizontally. 	Take the coefficient of static friction between the crate and floor to be 0.37.  Calculate the Fricitonal forces between the crate and the floor.	Is the man’s 100 N applied force enough to get the crate to move?	If a second man applies a horizontal, what minimum force, in addition to the 100 N force of the first man, must he exert to get the crate started?`
2 years ago

## Answers : (4)

downey zer
73 Points
```							max frictional force that can be applied if required will be fmax=uN= 0.37*35g
since 100 N max therefore block will not move and to make the net force on the block equal to zero frictional force will be equal to applied force always remember that friction opposes relative motion between two surfaces so it will do whatever it can (if it can) to stop relative motion
if second man applies a force slightly greater than fmax – 100 then the block will start to move as the net force on the block will become nonzero.
please approve the answer if it helped
```
2 years ago
downey zer
73 Points
```							in the second line it should be 100 > fmax
```
2 years ago
downey zer
73 Points
```							sorry 100max
i just keep making these silly mistakes sorry.
```
2 years ago
downey zer
73 Points
```							there is some problem in the less than sign
100 less than f max
this ought to do it.
```
2 years ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions