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A 20 kg block is in motion on a rough horizontal surface.a horizontal force of 60 N is required to keep the body moving with constant speed.the coefficient of kinetic friction is
m=20 kgF=μmgor μs=F/mg=60/20*98=60/196=0.306 Hope it helps RegardsArun (askIITians forum expert)
m=20 kg
F=μmg
or μs=F/mg
=60/20*98
=60/196=0.306
Hope it helps
Regards
Arun (askIITians forum expert)
m=20 kgF=μmgor μs=F/mg=60/20*98=60/196=0.306Hence u can do all questions like these Regards and wish u the best for jeeThnks Hope it helps
Hence u can do all questions like these
Regards and wish u the best for jee
Thnks
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