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A 2 kg block slides on a horizontal floor with a speed of 4 m/s. It strikes an uncompressed spring and compresses it till the block is motionless. The kinetic frictional force is 15 N and spring constant is 10000 N/m. The spring is compressed by ​(A) 8.5 cm(B) 5.5 cm(C) 2.5 cm(D) 11 cm

ananya bhat , 6 Years ago
Grade 11
anser 1 Answers
Arun

Last Activity: 6 Years ago

0.5 mv^2 = 0.5kx^2

x = v * sqrt( m / k )
= 4 * sqrt(2 / 10^4)
= 5.657 cm

Most correct option is (B) 5.5 cm

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