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A 1400-kg jet engine is fastened to the fuselage of a passenger jet by just three bolts (this is the usual practice.) Assume that each bolt support one-third of the load. (a) Calculate the force on each bolt as the plane waits in line for clearance to take off. (b) During flight, the plane encounters turbulence, which suddenly imparts an upward vertical acceleration of 2.60 m/s 2 to the plane. Calculate the force on each bolt now. Why are only three bolts used? See Fig. 3-30.
(a)First we have to find out the weight W of the engine.To obtain the weight of the engine W, substitute 1400 kg for mass m and 9.81 m/s2 for g in the equation W = mg,W = mg = (1400 kg) (9.81 m/s2) = 1.37×104 kg.m/s2 = (1.37×104 kg.m/s2) (1 N/1 kg.m/s2) = 1.37×104 NAs each bolt supports 1/3 of this force, thus the force F on a bolt will be,F = 1.37×104 N/3 =4600 N
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