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```
A 12-kg block of steel is at rest on a horizontal table. The coefficient of static friction between block and table is 0.52. (a) What is the magnitude of the horizontal force that will just start the block moving? (b) What is the magnitude of a force acting upward 62° from the horizontal that will just start the block moving? (c) If the force acts down at 62° from the horizontal, how large can it be without causing the block to move?
A 12-kg block of steel is at rest on a horizontal table. The coefficient of static friction between block and table is 0.52. (a) What is the magnitude of the horizontal force that will just start the block moving? (b) What is the magnitude of a force acting upward 62° from the horizontal that will just start the block moving? (c) If the force acts down at 62° from the horizontal, how large can it be without causing the block to move?

```
5 years ago

Navjyot Kalra
654 Points
```							Round off to two significant figures,F = 61 NTherefore the force experienced by the block when the force acts horizontally is 61 N.Round off to two significant figures,F = 66 NTherefore the force experienced by the block when the force acts at an angle of 62° upwards is 66 N .Round of to two significant figures,
```
5 years ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions