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Grade: 10

                        

A 10-kg object moves along the x axis. Its acceleration as a function of its position is shown in Fig. 11-25. What is the net work performed on the object as it moves from x = 0 to x = 8.0 m?

5 years ago

Answers : (3)

Hasan Naqvi
97 Points
							
From graph a = 2.5x;
 
We know
w = ∫F.dx
=m∫a.dx
=m∫2.5 x.dx
=2.5m x2/2
=2.5 * 10 * 8 * 8 /2
=800 N
5 years ago
Jitender Pal
askIITians Faculty
365 Points
							From the below figure slope (m) of the graph will be,
235-277_1.JPG
235-273_1.JPG
235-1870_1.JPG
5 years ago
Aadya
13 Points
							
∆KE = W 
The area under acceleration-displacement  curve gives = change in KE per unit mass
So, W = mass× area under curve
           =   10 x 1/2 × 8/100 ×20/100
            =   8/100 J
one year ago
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