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```
A 10-kg object moves along the x axis. Its acceleration as a function of its position is shown in Fig. 11-25. What is the net work performed on the object as it moves from x = 0 to x = 8.0 m?

```
5 years ago

## Answers : (3)

Hasan Naqvi
97 Points
```							From graph a = 2.5x; We knoww = ∫F.dx=m∫a.dx=m∫2.5 x.dx=2.5m x2/2=2.5 * 10 * 8 * 8 /2=800 N
```
5 years ago
Jitender Pal
365 Points
```							From the below figure slope (m) of the graph will be,
```
5 years ago
13 Points
```							∆KE = W The area under acceleration-displacement  curve gives = change in KE per unit massSo, W = mass× area under curve           =   10 x 1/2 × 8/100 ×20/100            =   8/100 J
```
one year ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions