A 1 kg mass is projected down a rough circular track (radius =2m ) placed in a vertical plane . The speed of mass at point p is 3m/s and at q is 6 m/s .How much work is done on the mass between the points p and q by the force of friction ? ( Take g= 10m/s^2)

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Khimraj · Answer

Please attach the image of track so point p and q are visible. ….................................................................

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A 1 kg mass is projected down a rough circular track (radius =2m ) placed in a vertical plane . The speed of mass at point p is 3m/s and at q is 6 m/s .How much work is done on the mass between the points p and q by the force of friction ? ( Take g= 10m/s^2)

A 1 kg mass is projected down a rough circular track (radius =2m ) placed in a vertical plane .
The speed of mass at point p is 3m/s and at q is 6 m/s .How much work is done on the mass between the points p and q by the force of friction ? ( Take g= 10m/s^2)

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A 1 kg mass is projected down a rough circular track (radius =2m ) placed in a vertical plane . The speed of mass at point p is 3m/s and at q is 6 m/s .How much work is done on the mass between the points p and q by the force of friction ? ( Take g= 10m/s^2)

A 1 kg mass is projected down a rough circular track (radius =2m ) placed in a vertical plane .The speed of mass at point p is 3m/s and at q is 6 m/s .How much work is done on the mass between the points p and q by the force of friction ? ( Take g= 10m/s^2)

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A 1 kg mass is projected down a rough circular track (radius =2m ) placed in a vertical plane .
The speed of mass at point p is 3m/s and at q is 6 m/s .How much work is done on the mass between the points p and q by the force of friction ? ( Take g= 10m/s^2)