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A 1.0-kg block of wood sits on top of an identical block of wood, which sits on top of a flat level table made of plastic. The coefficient of static friction between the wood surfaces is μ 1 , and the coefficient of static friction between the wood and plastic is i-t2' (a) A horizontal force F is applied to the top block only, and this force is increased until the top block starts to slide. The bottom block will slide with the top block if and only if (b) Instead a horizontal force F is applied to the bottom block only, and this force is increased until the bottom block just starts to slide. Under what conditions will the top block slide with the bottom block?

A 1.0-kg block of wood sits on top of an identical block of wood, which sits on top of a flat level table made of plastic. The coefficient of static friction between the wood surfaces is μ1 , and the coefficient of static friction between the wood and plastic is i-t2'
(a) A horizontal force F is applied to the top block only, and this force is increased until the top block starts to slide. The bottom block will slide with the top block if and only if
(b) Instead a horizontal force F is applied to the bottom block only, and this force is increased until the bottom block just starts to slide. Under what conditions will the top block slide with the bottom block?

Grade:11

1 Answers

Kevin Nash
askIITians Faculty 332 Points
8 years ago
The correct option is:
234-547_1.PNG
(a)
The figure below shows the forces acting on the block 1 resting on block 2:
234-1571_1.PNG
It can be seen from the figure above that when a force acts on block 1, the frictional force acts on the block in the opposite direction. When the block just begins to slide over the one beneath it, the frictional force experienced by it is the static force of frictions.
Therefore, when block 1 just begins to move, F = fs
Here, fs is the static force of friction between block 1 and block 2.
The static force of friction exerted by block 2 on block 1 is reacted by a force of same magnitude, but in opposite direction. Therefore, block 2 experiences a force fs in the forward direction and experiences a static force of friction f’s in the backward direction due to the contact forces between the plastic and its surface.
When block 2 just begins to move with block 1, the force fs should be greater than f’s , that is,

234-1583_1.PNG
Here, N1 is the normal force acting on block 1 and is equal to mg whereas N2 is the normal force acting on block 2, and is equal to 2mg ( m being the mass of block and g the free fall acceleration).

234-2153_1.PNG
Thus, the condition that should exist for block 2 to move with block 1 is 2μ2 < μ1. Therefore (D) is the correct option and the rest are ruled out
(b)

234-2175_1.PNG
Thus (A) is the correct option, while the rest are ruled out.

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