55 th question in the attachment........................................
sri harshitha honey , 5 Years ago
Grade 12
Mechanics> 55 th question in the attachment............
3 Answers
Arun
Last Activity: 5 Years ago
Let the charges are q1,q2
so q1=q2=2*10^(-16)C
distance,d=20cm so radius,r=d/2=5cm=5*10^(-2)m
force F=(10^(-9)*2*10^(-16)*2*10^(-16))/(9*25*10^(-4))
=1.77*10^(-39)N
Therefore electric field intensity, E=F/q
=8.88*10^(-24)volts
so q1=q2=2*10^(-16)C
distance,d=20cm so radius,r=d/2=5cm=5*10^(-2)m
force F=(10^(-9)*2*10^(-16)*2*10^(-16))/(9*25*10^(-4))
=1.77*10^(-39)N
Therefore electric field intensity, E=F/q
=8.88*10^(-24)volts
Vikas TU
Last Activity: 5 Years ago
Dear student
Let A s the midpoint
When charge is placed at A
E1 = kq1q2/r + kq3q4/r
E1 = 72*10^-4 J
When charge is placed at B , 20 cm from both charge,
E2 = Kq1q2/r + kq3q4/r
E2 = 36*10^-4 J
Work done = E1 - E2
= 3.6* 10^-3 J
Let A s the midpoint
When charge is placed at A
E1 = kq1q2/r + kq3q4/r
E1 = 72*10^-4 J
When charge is placed at B , 20 cm from both charge,
E2 = Kq1q2/r + kq3q4/r
E2 = 36*10^-4 J
Work done = E1 - E2
= 3.6* 10^-3 J
aswanth nayak
Last Activity: 4 Years ago
Dear student ,
Let A is the midpoint
When charge is placed at A
E1 = kq1q2/r + kq3q4/r
E1 = 72*10^-4 J
When charge is placed at B , 20 cm from both charge,
E2 = Kq1q2/r + kq3q4/r
E2 = 36*10^-4 J
Work done = E1 - E2
= 3.6* 10^-3 J
Regards
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