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`        5. An open glass tube is immersed in mercury in such a way that a length of 8 cm extends above the mercurylevel. The open end of the tube is then closed and sealed and the tube is raised vertically up by additional 46cm. What will be length of the air column above mercury in the tube now? (Atmospheric pressure = 76 cmof Hg)(1) 38 cm (2) 6 cm(3) 16 cm (4) 22 cm`
2 years ago

Taral Jain
39 Points
```							Answer is (3) - 16 cm.I`m giving you hint so think about it.(76) (8) = (54 – x) (76 – x)x = 38 cm ,  Length of air column = 54 – 38 = 16 cm
```
2 years ago
Taral Jain
39 Points
```							Dear student fing the solution below and ask any doubt.Using isothermal conditions8p1=xp Therefore, p=8p1/xNow,8p1/x+(rho)×g×(54-x)=(rho)×g×76Implies: 8/x+(54-x)/76=1Implies: x=16cm.
```
2 years ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions