Flag Mechanics> mechanics...
question mark

4. A ball is released from top of the tower of hight hm. It takes t sec. to reach the ground. What is the position of ball inT/3 sec.

mohit , 11 Years ago
Grade 8
anser 1 Answers
Ashish Kumar

Last Activity: 11 Years ago

h=1/2 gt^2 , t=sq.root( 2h/g)

in t/3 secs the height through which the ball will fall , H=1/2 gt^2/9= h/9 m
so position from the ground = h-h/9 = 8h/9 m



169-995_signature1.GIF

Provide a better Answer & Earn Cool Goodies

Enter text here...
star
LIVE ONLINE CLASSES

Prepraring for the competition made easy just by live online class.

tv

Full Live Access

material

Study Material

removal

Live Doubts Solving

assignment

Daily Class Assignments


Ask a Doubt

Get your questions answered by the expert for free

Enter text here...