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`        39 question in the  attachment.........................................................`
one month ago

Arun
23520 Points
```							The positive charge Q is uniformly distributed along the circular ring then electric field at the centre of ring will be zero, hence no force is experienced by the charge if it is placed at the centre of the ring.Now the charge is displaced away from the centre in the plane of the ring. There will be net electric field opposite to displacement will push back the charge towards the centre of the ring if the charge is positive. If charge is negative, it will experience net force in the direction of displacement and the charge will continue moving till it hits the ring. Also this negative charge is in an unstable equilibrium
```
one month ago
Vikas TU
10070 Points
```							Dear student F = KQq/R^2 a = d^2x /dt^2 = - KQqx/m(R^2+x^2)^1.5for x very greater than R d^2x /dt^2 = - KQqx/mR^2 d^2x /dt^2 = -w^2 x w = sqrt(KQq/mR^2)T = 2pie/w T = 2pie/sqrt(KQq/mR^2)
```
one month ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions